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212013341 = 1712471373
BaseRepresentation
bin11001010001100…
…01000100011101
3112202221101121222
430220301010131
5413233411331
633012103125
75153040461
oct1450610435
9482841558
10212013341
11a9748841
125b004aa5
1334c023a7
142022c4a1
151392db7b
hexca3111d

212013341 has 4 divisors (see below), whose sum is σ = 224484732. Its totient is φ = 199541952.

The previous prime is 212013323. The next prime is 212013353. The reversal of 212013341 is 143310212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 98505625 + 113507716 = 9925^2 + 10654^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212013341 is a prime.

It is a super-3 number, since 3×2120133413 (a number of 26 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (17), and also a Moran number because the ratio is a prime number: 12471373 = 212013341 / (2 + 1 + 2 + 0 + 1 + 3 + 3 + 4 + 1).

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212013301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6235670 + ... + 6235703.

It is an arithmetic number, because the mean of its divisors is an integer number (56121183).

Almost surely, 2212013341 is an apocalyptic number.

It is an amenable number.

212013341 is a deficient number, since it is larger than the sum of its proper divisors (12471391).

212013341 is a wasteful number, since it uses less digits than its factorization.

212013341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12471390.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 212013341 is about 14560.6779031747. The cubic root of 212013341 is about 596.2857031861.

Adding to 212013341 its reverse (143310212), we get a palindrome (355323553).

It can be divided in two parts, 21201 and 3341, that added together give a palindrome (24542).

The spelling of 212013341 in words is "two hundred twelve million, thirteen thousand, three hundred forty-one".

Divisors: 1 17 12471373 212013341