Base | Representation |
---|---|
bin | 110000001101001101011011… |
… | …110001110101010010110111 |
3 | 1000210200100012220210100212020 |
4 | 300031031123301311102313 |
5 | 210242114143132004310 |
6 | 2030525520343324223 |
7 | 62441335552054653 |
oct | 6015153361652267 |
9 | 1023610186710766 |
10 | 212014010422455 |
11 | 6161070076498a |
12 | 1b94189b150673 |
13 | 913bab2499567 |
14 | 3a4d76622da63 |
15 | 1979e86ea1170 |
hex | c0d35bc754b7 |
212014010422455 has 16 divisors (see below), whose sum is σ = 339223157867520. Its totient is φ = 113073891828128.
The previous prime is 212014010422441. The next prime is 212014010422457. The reversal of 212014010422455 is 554224010410212.
It is a cyclic number.
It is not a de Polignac number, because 212014010422455 - 24 = 212014010422439 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212014010422457) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 8239215 + ... + 22179104.
It is an arithmetic number, because the mean of its divisors is an integer number (21201447366720).
Almost surely, 2212014010422455 is an apocalyptic number.
212014010422455 is a deficient number, since it is larger than the sum of its proper divisors (127209147445065).
212014010422455 is a wasteful number, since it uses less digits than its factorization.
212014010422455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30882990.
The product of its (nonzero) digits is 25600, while the sum is 33.
Adding to 212014010422455 its reverse (554224010410212), we get a palindrome (766238020832667).
The spelling of 212014010422455 in words is "two hundred twelve trillion, fourteen billion, ten million, four hundred twenty-two thousand, four hundred fifty-five".
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