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212014113 = 3541130631
BaseRepresentation
bin11001010001100…
…01010000100001
3112202221102200120
430220301100201
5413233422423
633012110453
75153042643
oct1450612041
9482842616
10212014113
11a9749383
125b005429
1334c0284c
142022c893
151392dee3
hexca31421

212014113 has 8 divisors (see below), whose sum is σ = 283210176. Its totient is φ = 141080400.

The previous prime is 212014111. The next prime is 212014147. The reversal of 212014113 is 311410212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 212014113 - 21 = 212014111 is a prime.

It is a super-2 number, since 2×2120141132 = 89899968222353538, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 212014092 and 212014101.

It is not an unprimeable number, because it can be changed into a prime (212014111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 63693 + ... + 66938.

It is an arithmetic number, because the mean of its divisors is an integer number (35401272).

Almost surely, 2212014113 is an apocalyptic number.

It is an amenable number.

212014113 is a deficient number, since it is larger than the sum of its proper divisors (71196063).

212014113 is a wasteful number, since it uses less digits than its factorization.

212014113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131175.

The product of its (nonzero) digits is 48, while the sum is 15.

The square root of 212014113 is about 14560.7044129053. The cubic root of 212014113 is about 596.2864269330.

Adding to 212014113 its reverse (311410212), we get a palindrome (523424325).

The spelling of 212014113 in words is "two hundred twelve million, fourteen thousand, one hundred thirteen".

Divisors: 1 3 541 1623 130631 391893 70671371 212014113