Base | Representation |
---|---|
bin | 11001010001100… |
… | …01010001000011 |
3 | 112202221102201211 |
4 | 30220301101003 |
5 | 413233423042 |
6 | 33012110551 |
7 | 5153043022 |
oct | 1450612103 |
9 | 482842654 |
10 | 212014147 |
11 | a9749404 |
12 | 5b005457 |
13 | 34c02877 |
14 | 2022c8b9 |
15 | 1392e017 |
hex | ca31443 |
212014147 has 2 divisors, whose sum is σ = 212014148. Its totient is φ = 212014146.
The previous prime is 212014111. The next prime is 212014189. The reversal of 212014147 is 741410212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212014147 is a prime.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (212014247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106007073 + 106007074.
It is an arithmetic number, because the mean of its divisors is an integer number (106007074).
Almost surely, 2212014147 is an apocalyptic number.
212014147 is a deficient number, since it is larger than the sum of its proper divisors (1).
212014147 is an equidigital number, since it uses as much as digits as its factorization.
212014147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 448, while the sum is 22.
The square root of 212014147 is about 14560.7055804312. The cubic root of 212014147 is about 596.2864588078.
Adding to 212014147 its reverse (741410212), we get a palindrome (953424359).
The spelling of 212014147 in words is "two hundred twelve million, fourteen thousand, one hundred forty-seven".
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