Base | Representation |
---|---|
bin | 1100010101110100001… |
… | …0000010110100100001 |
3 | 202021020122011000101100 |
4 | 3011131002002310201 |
5 | 11433201114330213 |
6 | 241221544225013 |
7 | 21213624042150 |
oct | 3053502026441 |
9 | 667218130340 |
10 | 212014214433 |
11 | 81a0755133a |
12 | 3510b16b169 |
13 | 16cba3bc8b8 |
14 | a39395d597 |
15 | 57ad0a1773 |
hex | 315d082d21 |
212014214433 has 24 divisors (see below), whose sum is σ = 350014491008. Its totient is φ = 121143097152.
The previous prime is 212014214387. The next prime is 212014214491. The reversal of 212014214433 is 334412410212.
212014214433 is a `hidden beast` number, since 2 + 1 + 2 + 0 + 14 + 214 + 433 = 666.
It is not a de Polignac number, because 212014214433 - 28 = 212014214177 is a prime.
It is a super-2 number, since 2×2120142144332 (a number of 23 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 212014214397 and 212014214406.
It is not an unprimeable number, because it can be changed into a prime (212014614433) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 946716 + ... + 1149042.
Almost surely, 2212014214433 is an apocalyptic number.
It is an amenable number.
212014214433 is a deficient number, since it is larger than the sum of its proper divisors (138000276575).
212014214433 is a wasteful number, since it uses less digits than its factorization.
212014214433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 218973 (or 218970 counting only the distinct ones).
The product of its (nonzero) digits is 4608, while the sum is 27.
Adding to 212014214433 its reverse (334412410212), we get a palindrome (546426624645).
The spelling of 212014214433 in words is "two hundred twelve billion, fourteen million, two hundred fourteen thousand, four hundred thirty-three".
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