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212023141315 = 5116993624637
BaseRepresentation
bin1100010101110110010…
…0000110001111000011
3202021021020221112202121
43011131210012033003
511433210411010230
6241222503425111
721214062652066
oct3053544061703
9667236845677
10212023141315
1181a11599227
1235112155197
1316cbc1c6b8b
14a394c048dd
1557adc6677a
hex315d9063c3

212023141315 has 8 divisors (see below), whose sum is σ = 254449587600. Its totient is φ = 169603967712.

The previous prime is 212023141303. The next prime is 212023141367. The reversal of 212023141315 is 513141320212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 212023141315 - 221 = 212021044163 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 212023141315.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1753824 + ... + 1870813.

It is an arithmetic number, because the mean of its divisors is an integer number (31806198450).

Almost surely, 2212023141315 is an apocalyptic number.

212023141315 is a deficient number, since it is larger than the sum of its proper divisors (42426446285).

212023141315 is a wasteful number, since it uses less digits than its factorization.

212023141315 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3636341.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 212023141315 its reverse (513141320212), we get a palindrome (725164461527).

The spelling of 212023141315 in words is "two hundred twelve billion, twenty-three million, one hundred forty-one thousand, three hundred fifteen".

Divisors: 1 5 11699 58495 3624637 18123185 42404628263 212023141315