2120253433 has 4 divisors (see below), whose sum is σ = 2155011748. Its totient is φ = 2085495120.

The previous prime is 2120253431. The next prime is 2120253437. The reversal of 2120253433 is 3343520212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 682933689 + 1437319744 = 26133^2 + 37912^2 .

It is a cyclic number.

It is not a de Polignac number, because 2120253433 - 2¹ = 2120253431 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 2120253398 and 2120253407.

It is not an unprimeable number, because it can be changed into a prime (2120253431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17379066 + ... + 17379187.

It is an arithmetic number, because the mean of its divisors is an integer number (538752937).

Almost surely, 2^2120253433 is an apocalyptic number.

It is an amenable number.

2120253433 is a deficient number, since it is larger than the sum of its proper divisors (34758315).

2120253433 is an equidigital number, since it uses as much as digits as its factorization.

2120253433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34758314.

The product of its (nonzero) digits is 4320, while the sum is 25.

The square root of 2120253433 is about 46046.2097571559. The cubic root of 2120253433 is about 1284.6828456185.

Adding to 2120253433 its reverse (3343520212), we get a palindrome (5463773645).

The spelling of 2120253433 in words is "two billion, one hundred twenty million, two hundred fifty-three thousand, four hundred thirty-three".