Base | Representation |
---|---|
bin | 11110110110101011110… |
… | …111000000010100101111 |
3 | 21111200212111122211002020 |
4 | 132312223313000110233 |
5 | 234214334330400421 |
6 | 4302015310401223 |
7 | 306121031222244 |
oct | 36665367002457 |
9 | 7450774584066 |
10 | 2120302200111 |
11 | 748240352367 |
12 | 2a2b18b00213 |
13 | 124c36239a74 |
14 | 748a1dbd5cb |
15 | 3a249778dc6 |
hex | 1edabdc052f |
2120302200111 has 16 divisors (see below), whose sum is σ = 2837352069120. Its totient is φ = 1408394352960.
The previous prime is 2120302200089. The next prime is 2120302200119. The reversal of 2120302200111 is 1110022030212.
It is not a de Polignac number, because 2120302200111 - 29 = 2120302199599 is a prime.
It is a super-3 number, since 3×21203022001113 (a number of 38 digits) contains 333 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2120302200119) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11507436 + ... + 11690238.
It is an arithmetic number, because the mean of its divisors is an integer number (177334504320).
Almost surely, 22120302200111 is an apocalyptic number.
2120302200111 is a deficient number, since it is larger than the sum of its proper divisors (717049869009).
2120302200111 is a wasteful number, since it uses less digits than its factorization.
2120302200111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 196846.
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 2120302200111 its reverse (1110022030212), we get a palindrome (3230324230323).
The spelling of 2120302200111 in words is "two trillion, one hundred twenty billion, three hundred two million, two hundred thousand, one hundred eleven".
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