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2120311310122 = 21060155655061
BaseRepresentation
bin11110110110101100011…
…001110000011100101010
321111200220010210122200001
4132312230121300130222
5234214344143410442
64302020233533214
7306121201524115
oct36665431603452
97450803718601
102120311310122
117482455048a5
122a2b1bb7420a
13124c380a94c5
14748a32b157c
153a24a4782b7
hex1edac67072a

2120311310122 has 4 divisors (see below), whose sum is σ = 3180466965186. Its totient is φ = 1060155655060.

The previous prime is 2120311310083. The next prime is 2120311310129. The reversal of 2120311310122 is 2210131130212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1252248283521 + 868063026601 = 1119039^2 + 931699^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 2120311310122.

It is not an unprimeable number, because it can be changed into a prime (2120311310129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 530077827529 + ... + 530077827532.

Almost surely, 22120311310122 is an apocalyptic number.

2120311310122 is a deficient number, since it is larger than the sum of its proper divisors (1060155655064).

2120311310122 is a wasteful number, since it uses less digits than its factorization.

2120311310122 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1060155655063.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 2120311310122 its reverse (2210131130212), we get a palindrome (4330442440334).

The spelling of 2120311310122 in words is "two trillion, one hundred twenty billion, three hundred eleven million, three hundred ten thousand, one hundred twenty-two".

Divisors: 1 2 1060155655061 2120311310122