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212043430051 = 1911160180529
BaseRepresentation
bin1100010101111011000…
…1011111100010100011
3202021022200010022200021
43011132301133202203
511433231104230201
6241224510334311
721214430262655
oct3053661374243
9667280108607
10212043430051
1181a21a96482
1235118aba397
1316cc347b84b
14a3977a66d5
1557b0922ea1
hex315ec5f8a3

212043430051 has 4 divisors (see below), whose sum is σ = 223203610600. Its totient is φ = 200883249504.

The previous prime is 212043429979. The next prime is 212043430073. The reversal of 212043430051 is 150034340212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 212043430051 - 215 = 212043397283 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212043429998 and 212043430025.

It is not an unprimeable number, because it can be changed into a prime (212044430051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5580090246 + ... + 5580090283.

It is an arithmetic number, because the mean of its divisors is an integer number (55800902650).

Almost surely, 2212043430051 is an apocalyptic number.

212043430051 is a deficient number, since it is larger than the sum of its proper divisors (11160180549).

212043430051 is a wasteful number, since it uses less digits than its factorization.

212043430051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11160180548.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 212043430051 its reverse (150034340212), we get a palindrome (362077770263).

The spelling of 212043430051 in words is "two hundred twelve billion, forty-three million, four hundred thirty thousand, fifty-one".

Divisors: 1 19 11160180529 212043430051