Base | Representation |
---|---|
bin | 1100010101111011000… |
… | …1011111100010100011 |
3 | 202021022200010022200021 |
4 | 3011132301133202203 |
5 | 11433231104230201 |
6 | 241224510334311 |
7 | 21214430262655 |
oct | 3053661374243 |
9 | 667280108607 |
10 | 212043430051 |
11 | 81a21a96482 |
12 | 35118aba397 |
13 | 16cc347b84b |
14 | a3977a66d5 |
15 | 57b0922ea1 |
hex | 315ec5f8a3 |
212043430051 has 4 divisors (see below), whose sum is σ = 223203610600. Its totient is φ = 200883249504.
The previous prime is 212043429979. The next prime is 212043430073. The reversal of 212043430051 is 150034340212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 212043430051 - 215 = 212043397283 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 212043429998 and 212043430025.
It is not an unprimeable number, because it can be changed into a prime (212044430051) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5580090246 + ... + 5580090283.
It is an arithmetic number, because the mean of its divisors is an integer number (55800902650).
Almost surely, 2212043430051 is an apocalyptic number.
212043430051 is a deficient number, since it is larger than the sum of its proper divisors (11160180549).
212043430051 is a wasteful number, since it uses less digits than its factorization.
212043430051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11160180548.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 212043430051 its reverse (150034340212), we get a palindrome (362077770263).
The spelling of 212043430051 in words is "two hundred twelve billion, forty-three million, four hundred thirty thousand, fifty-one".
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