Base | Representation |
---|---|
bin | 11001010010001… |
… | …10101111100001 |
3 | 112210002220101211 |
4 | 30221012233201 |
5 | 413244231423 |
6 | 33014030121 |
7 | 5153560336 |
oct | 1451065741 |
9 | 483086354 |
10 | 212102113 |
11 | a97a9503 |
12 | 5b048341 |
13 | 34c33912 |
14 | 2025298d |
15 | 1394a10d |
hex | ca46be1 |
212102113 has 4 divisors (see below), whose sum is σ = 221323968. Its totient is φ = 202880260.
The previous prime is 212102089. The next prime is 212102153. The reversal of 212102113 is 311201212.
212102113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 212102113 - 217 = 211971041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 212102093 and 212102102.
It is not an unprimeable number, because it can be changed into a prime (212102153) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4610893 + ... + 4610938.
It is an arithmetic number, because the mean of its divisors is an integer number (55330992).
Almost surely, 2212102113 is an apocalyptic number.
212102113 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
212102113 is a deficient number, since it is larger than the sum of its proper divisors (9221855).
212102113 is an equidigital number, since it uses as much as digits as its factorization.
212102113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9221854.
The product of its (nonzero) digits is 24, while the sum is 13.
The square root of 212102113 is about 14563.7259312306. The cubic root of 212102113 is about 596.3689150695.
Adding to 212102113 its reverse (311201212), we get a palindrome (523303325).
Subtracting 212102113 from its reverse (311201212), we obtain a palindrome (99099099).
The spelling of 212102113 in words is "two hundred twelve million, one hundred two thousand, one hundred thirteen".
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