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212122001103 = 3464915209149
BaseRepresentation
bin1100010110001101110…
…1001101111011001111
3202021112010222010220020
43011203131031323033
511433411213013403
6241240354353223
721216403155045
oct3054335157317
9667463863806
10212122001103
1181a62381031
123513b28b813
131700682b6ac
14a3a3dba395
1557b7793453
hex316374decf

212122001103 has 8 divisors (see below), whose sum is σ = 282890190000. Its totient is φ = 141384239808.

The previous prime is 212122001087. The next prime is 212122001137. The reversal of 212122001103 is 301100221212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 212122001103 - 24 = 212122001087 is a prime.

It is a super-2 number, since 2×2121220011032 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212122001303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7590628 + ... + 7618521.

It is an arithmetic number, because the mean of its divisors is an integer number (35361273750).

Almost surely, 2212122001103 is an apocalyptic number.

212122001103 is a deficient number, since it is larger than the sum of its proper divisors (70768188897).

212122001103 is a wasteful number, since it uses less digits than its factorization.

212122001103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15213801.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 212122001103 its reverse (301100221212), we get a palindrome (513222222315).

The spelling of 212122001103 in words is "two hundred twelve billion, one hundred twenty-two million, one thousand, one hundred three".

Divisors: 1 3 4649 13947 15209149 45627447 70707333701 212122001103