Base | Representation |
---|---|
bin | 110000001110111100010000… |
… | …000111000011001000101100 |
3 | 1000211002201100111200012101102 |
4 | 300032330100013003020230 |
5 | 210301041341000000134 |
6 | 2031100315503102232 |
7 | 62453050331560304 |
oct | 6016742007031054 |
9 | 1024081314605342 |
10 | 212133000000044 |
11 | 61657111227762 |
12 | 1b9609685a1978 |
13 | 914a096237836 |
14 | 3a554132b4604 |
15 | 197d0ed3b737e |
hex | c0ef101c322c |
212133000000044 has 12 divisors (see below), whose sum is σ = 372059549001000. Its totient is φ = 105830271714048.
The previous prime is 212133000000041. The next prime is 212133000000067. The reversal of 212133000000044 is 440000000331212.
It is a junction number, because it is equal to n+sod(n) for n = 212132999999962 and 212133000000025.
It is not an unprimeable number, because it can be changed into a prime (212133000000041) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 59057069474 + ... + 59057073065.
It is an arithmetic number, because the mean of its divisors is an integer number (31004962416750).
Almost surely, 2212133000000044 is an apocalyptic number.
It is an amenable number.
212133000000044 is a deficient number, since it is larger than the sum of its proper divisors (159926549000956).
212133000000044 is a wasteful number, since it uses less digits than its factorization.
212133000000044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 118114142992 (or 118114142990 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 212133000000044 its reverse (440000000331212), we get a palindrome (652133000331256).
The spelling of 212133000000044 in words is "two hundred twelve trillion, one hundred thirty-three billion, forty-four", and thus it is an aban number.
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