Base | Representation |
---|---|
bin | 1100010110010011001… |
… | …0010010010101011011 |
3 | 202021120200221010011021 |
4 | 3011210302102111123 |
5 | 11433432420121103 |
6 | 241242512343311 |
7 | 21220063544356 |
oct | 3054462222533 |
9 | 667520833137 |
10 | 212144301403 |
11 | 81a73a22631 |
12 | 35146844b37 |
13 | 1700b338b38 |
14 | a3a6d4329d |
15 | 57b96eabbd |
hex | 3164c9255b |
212144301403 has 4 divisors (see below), whose sum is σ = 212190214768. Its totient is φ = 212098388040.
The previous prime is 212144301389. The next prime is 212144301497. The reversal of 212144301403 is 304103441212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 212144301403 - 213 = 212144293211 is a prime.
It is a super-3 number, since 3×2121443014033 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (212144308403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22949751 + ... + 22958992.
It is an arithmetic number, because the mean of its divisors is an integer number (53047553692).
Almost surely, 2212144301403 is an apocalyptic number.
212144301403 is a deficient number, since it is larger than the sum of its proper divisors (45913365).
212144301403 is an equidigital number, since it uses as much as digits as its factorization.
212144301403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 45913364.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 212144301403 its reverse (304103441212), we get a palindrome (516247742615).
The spelling of 212144301403 in words is "two hundred twelve billion, one hundred forty-four million, three hundred one thousand, four hundred three".
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