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21214441103 = 61347777723
BaseRepresentation
bin10011110000011110…
…101010111010001111
32000202110201021020212
4103300132222322033
5321421344103403
613425031033035
71350466526342
oct236036527217
960673637225
1021214441103
118aa6aa9659
12414080b77b
13200118723b
1410536d4459
158426aa4d8
hex4f07aae8f

21214441103 has 4 divisors (see below), whose sum is σ = 21562218888. Its totient is φ = 20866663320.

The previous prime is 21214441097. The next prime is 21214441111. The reversal of 21214441103 is 30114441212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21214441103 - 212 = 21214437007 is a prime.

It is a super-2 number, since 2×212144411032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21214441133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 173888801 + ... + 173888922.

It is an arithmetic number, because the mean of its divisors is an integer number (5390554722).

Almost surely, 221214441103 is an apocalyptic number.

21214441103 is a deficient number, since it is larger than the sum of its proper divisors (347777785).

21214441103 is an equidigital number, since it uses as much as digits as its factorization.

21214441103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 347777784.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 21214441103 its reverse (30114441212), we get a palindrome (51328882315).

The spelling of 21214441103 in words is "twenty-one billion, two hundred fourteen million, four hundred forty-one thousand, one hundred three".

Divisors: 1 61 347777723 21214441103