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2121452455351 = 17124791320903
BaseRepresentation
bin11110110111110000011…
…010111000010110110111
321111210211200001211122011
4132313300122320112313
5234224213312032401
64302325400345051
7306161366225125
oct36676032702667
97453750054564
102121452455351
11748780672129
122a319a175187
1312508a635078
1474970a80915
153a2b573a451
hex1edf06b85b7

2121452455351 has 4 divisors (see below), whose sum is σ = 2246243776272. Its totient is φ = 1996661134432.

The previous prime is 2121452455321. The next prime is 2121452455357. The reversal of 2121452455351 is 1535542541212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2121452455351 - 27 = 2121452455223 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2121452455357) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 62395660435 + ... + 62395660468.

It is an arithmetic number, because the mean of its divisors is an integer number (561560944068).

Almost surely, 22121452455351 is an apocalyptic number.

2121452455351 is a deficient number, since it is larger than the sum of its proper divisors (124791320921).

2121452455351 is a wasteful number, since it uses less digits than its factorization.

2121452455351 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 124791320920.

The product of its digits is 240000, while the sum is 40.

Adding to 2121452455351 its reverse (1535542541212), we get a palindrome (3656994996563).

The spelling of 2121452455351 in words is "two trillion, one hundred twenty-one billion, four hundred fifty-two million, four hundred fifty-five thousand, three hundred fifty-one".

Divisors: 1 17 124791320903 2121452455351