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2122104141403 = 9455922442117
BaseRepresentation
bin11110111000010111010…
…000110111011001011011
321111212112002022220211121
4132320113100313121123
5234232032130011103
64302514200310111
7306213501403351
oct36702720673133
97455462286747
102122104141403
11748a85512544
122a3340472337
1312516265960c
14749d343d7d1
153a302a676bd
hex1ee1743765b

2122104141403 has 4 divisors (see below), whose sum is σ = 2122126678080. Its totient is φ = 2122081604728.

The previous prime is 2122104141383. The next prime is 2122104141473. The reversal of 2122104141403 is 3041414012212.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2122104141403 - 213 = 2122104133211 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2122104141473) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11126500 + ... + 11315617.

It is an arithmetic number, because the mean of its divisors is an integer number (530531669520).

Almost surely, 22122104141403 is an apocalyptic number.

2122104141403 is a deficient number, since it is larger than the sum of its proper divisors (22536677).

2122104141403 is an equidigital number, since it uses as much as digits as its factorization.

2122104141403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22536676.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 2122104141403 its reverse (3041414012212), we get a palindrome (5163518153615).

The spelling of 2122104141403 in words is "two trillion, one hundred twenty-two billion, one hundred four million, one hundred forty-one thousand, four hundred three".

Divisors: 1 94559 22442117 2122104141403