Base | Representation |
---|---|
bin | 10011110001000011… |
… | …111110111011100001 |
3 | 2000210011010012201100 |
4 | 103301003332323201 |
5 | 321431400104213 |
6 | 13430020425013 |
7 | 1350645625341 |
oct | 236103767341 |
9 | 60704105640 |
10 | 21224222433 |
11 | 900157a4a7 |
12 | 4143b48169 |
13 | 20032003cb |
14 | 1054b1cd21 |
15 | 84348d773 |
hex | 4f10feee1 |
21224222433 has 48 divisors (see below), whose sum is σ = 31394563200. Its totient is φ = 13814530560.
The previous prime is 21224222423. The next prime is 21224222471. The reversal of 21224222433 is 33422242212.
21224222433 is a `hidden beast` number, since 2 + 1 + 2 + 2 + 4 + 222 + 433 = 666.
It is not a de Polignac number, because 21224222433 - 213 = 21224214241 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21224222397 and 21224222406.
It is not an unprimeable number, because it can be changed into a prime (21224222423) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 25296628 + ... + 25297466.
It is an arithmetic number, because the mean of its divisors is an integer number (654053400).
Almost surely, 221224222433 is an apocalyptic number.
It is an amenable number.
21224222433 is a deficient number, since it is larger than the sum of its proper divisors (10170340767).
21224222433 is a wasteful number, since it uses less digits than its factorization.
21224222433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1302 (or 1299 counting only the distinct ones).
The product of its digits is 9216, while the sum is 27.
Adding to 21224222433 its reverse (33422242212), we get a palindrome (54646464645).
The spelling of 21224222433 in words is "twenty-one billion, two hundred twenty-four million, two hundred twenty-two thousand, four hundred thirty-three".
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