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2122440121131 = 311115035591269
BaseRepresentation
bin11110111000101011010…
…010100001101100101011
321111220101111112110101020
4132320223102201230223
5234233224132334011
64303011401423523
7306225021235161
oct36705322415453
97456344473336
102122440121131
11749138131040
122a3414a9aba3
131251b71440a5
1474a25cdb231
153a3222d2006
hex1ee2b4a1b2b

2122440121131 has 16 divisors (see below), whose sum is σ = 3087454563840. Its totient is φ = 1286215290720.

The previous prime is 2122440121073. The next prime is 2122440121133. The reversal of 2122440121131 is 1311210442212.

It is not a de Polignac number, because 2122440121131 - 222 = 2122435926827 is a prime.

It is a super-2 number, since 2×21224401211312 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (2122440121133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2416036 + ... + 3175233.

It is an arithmetic number, because the mean of its divisors is an integer number (192965910240).

Almost surely, 22122440121131 is an apocalyptic number.

2122440121131 is a deficient number, since it is larger than the sum of its proper divisors (965014442709).

2122440121131 is a wasteful number, since it uses less digits than its factorization.

2122440121131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5602786.

The product of its (nonzero) digits is 768, while the sum is 24.

Adding to 2122440121131 its reverse (1311210442212), we get a palindrome (3433650563343).

The spelling of 2122440121131 in words is "two trillion, one hundred twenty-two billion, four hundred forty million, one hundred twenty-one thousand, one hundred thirty-one".

Divisors: 1 3 11 33 11503 34509 126533 379599 5591269 16773807 61503959 184511877 64316367307 192949101921 707480040377 2122440121131