Base | Representation |
---|---|
bin | 11110111000101011010… |
… | …010100001101100101011 |
3 | 21111220101111112110101020 |
4 | 132320223102201230223 |
5 | 234233224132334011 |
6 | 4303011401423523 |
7 | 306225021235161 |
oct | 36705322415453 |
9 | 7456344473336 |
10 | 2122440121131 |
11 | 749138131040 |
12 | 2a3414a9aba3 |
13 | 1251b71440a5 |
14 | 74a25cdb231 |
15 | 3a3222d2006 |
hex | 1ee2b4a1b2b |
2122440121131 has 16 divisors (see below), whose sum is σ = 3087454563840. Its totient is φ = 1286215290720.
The previous prime is 2122440121073. The next prime is 2122440121133. The reversal of 2122440121131 is 1311210442212.
It is not a de Polignac number, because 2122440121131 - 222 = 2122435926827 is a prime.
It is a super-2 number, since 2×21224401211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (2122440121133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2416036 + ... + 3175233.
It is an arithmetic number, because the mean of its divisors is an integer number (192965910240).
Almost surely, 22122440121131 is an apocalyptic number.
2122440121131 is a deficient number, since it is larger than the sum of its proper divisors (965014442709).
2122440121131 is a wasteful number, since it uses less digits than its factorization.
2122440121131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5602786.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 2122440121131 its reverse (1311210442212), we get a palindrome (3433650563343).
The spelling of 2122440121131 in words is "two trillion, one hundred twenty-two billion, four hundred forty million, one hundred twenty-one thousand, one hundred thirty-one".
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