Base | Representation |
---|---|
bin | 110000010001011000101111… |
… | …100110010011101000100011 |
3 | 1000211200210001221112211212121 |
4 | 300101120233212103220203 |
5 | 210311320003143343243 |
6 | 2031305425300205111 |
7 | 62501146325243032 |
oct | 6021305746235043 |
9 | 1024623057484777 |
10 | 212301032012323 |
11 | 617113a89925a1 |
12 | 1b989442099797 |
13 | 915cb94545437 |
14 | 3a5d5d3826719 |
15 | 19826850751ed |
hex | c1162f993a23 |
212301032012323 has 4 divisors (see below), whose sum is σ = 212310195976960. Its totient is φ = 212291868047688.
The previous prime is 212301032012243. The next prime is 212301032012371. The reversal of 212301032012323 is 323210230103212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212301032012323 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (212301032012723) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4581947568 + ... + 4581993901.
It is an arithmetic number, because the mean of its divisors is an integer number (53077548994240).
Almost surely, 2212301032012323 is an apocalyptic number.
212301032012323 is a deficient number, since it is larger than the sum of its proper divisors (9163964637).
212301032012323 is an equidigital number, since it uses as much as digits as its factorization.
212301032012323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9163964636.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 212301032012323 its reverse (323210230103212), we get a palindrome (535511262115535).
The spelling of 212301032012323 in words is "two hundred twelve trillion, three hundred one billion, thirty-two million, twelve thousand, three hundred twenty-three".
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