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2123133144001 = 2774376528607
BaseRepresentation
bin11110111001010100100…
…110001100101111000001
321111222011210120200000221
4132321110212030233001
5234241134041102001
64303204235343041
7306251134650052
oct36712446145701
97458153520027
102123133144001
11749463345411
122a3588bb1a81
131252978ac7ac
1474a8dd7a729
153a3630771a1
hex1ee5498cbc1

2123133144001 has 4 divisors (see below), whose sum is σ = 2123209700352. Its totient is φ = 2123056587652.

The previous prime is 2123133143981. The next prime is 2123133144007. The reversal of 2123133144001 is 1004413313212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2123133144001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2123133144007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 38236561 + ... + 38292046.

It is an arithmetic number, because the mean of its divisors is an integer number (530802425088).

Almost surely, 22123133144001 is an apocalyptic number.

It is an amenable number.

2123133144001 is a deficient number, since it is larger than the sum of its proper divisors (76556351).

2123133144001 is an equidigital number, since it uses as much as digits as its factorization.

2123133144001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 76556350.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2123133144001 its reverse (1004413313212), we get a palindrome (3127546457213).

The spelling of 2123133144001 in words is "two trillion, one hundred twenty-three billion, one hundred thirty-three million, one hundred forty-four thousand, one".

Divisors: 1 27743 76528607 2123133144001