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212403352423999 = 1119309395674909
BaseRepresentation
bin110000010010111000000010…
…010111101100111000111111
31000212001120011211110022112111
4300102320002113230320333
5210320004031210031444
62031424430353514451
762511431036345122
oct6022700227547077
91025046154408474
10212403352423999
11617508351102a0
121b9a5238b72a27
13916971c9c5929
143a6453cb0a3b9
151985172d64234
hexc12e025ece3f

212403352423999 has 4 divisors (see below), whose sum is σ = 231712748098920. Its totient is φ = 193093956749080.

The previous prime is 212403352423987. The next prime is 212403352424051. The reversal of 212403352423999 is 999324253304212.

212403352423999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 212403352423999 - 29 = 212403352423487 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212403352423909) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9654697837444 + ... + 9654697837465.

It is an arithmetic number, because the mean of its divisors is an integer number (57928187024730).

Almost surely, 2212403352423999 is an apocalyptic number.

212403352423999 is a deficient number, since it is larger than the sum of its proper divisors (19309395674921).

212403352423999 is a wasteful number, since it uses less digits than its factorization.

212403352423999 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19309395674920.

The product of its (nonzero) digits is 25194240, while the sum is 58.

The spelling of 212403352423999 in words is "two hundred twelve trillion, four hundred three billion, three hundred fifty-two million, four hundred twenty-three thousand, nine hundred ninety-nine".

Divisors: 1 11 19309395674909 212403352423999