Base | Representation |
---|---|
bin | 11110111010001010101… |
… | …010100000110011100111 |
3 | 21112001112000110010221001 |
4 | 132322022222200303213 |
5 | 234300013300310310 |
6 | 4303434241534131 |
7 | 306312461120563 |
oct | 36721252406347 |
9 | 7461460403831 |
10 | 2124040244455 |
11 | 749889387408 |
12 | 2a37a0944347 |
13 | 1253b07c101c |
14 | 74b386246a3 |
15 | 3a3b7a0793a |
hex | 1ee8aaa0ce7 |
2124040244455 has 4 divisors (see below), whose sum is σ = 2548848293352. Its totient is φ = 1699232195560.
The previous prime is 2124040244411. The next prime is 2124040244483. The reversal of 2124040244455 is 5544420404212.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 2124040244455 - 27 = 2124040244327 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 212404024441 + ... + 212404024450.
It is an arithmetic number, because the mean of its divisors is an integer number (637212073338).
Almost surely, 22124040244455 is an apocalyptic number.
2124040244455 is a deficient number, since it is larger than the sum of its proper divisors (424808048897).
2124040244455 is an equidigital number, since it uses as much as digits as its factorization.
2124040244455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 424808048896.
The product of its (nonzero) digits is 204800, while the sum is 37.
Adding to 2124040244455 its reverse (5544420404212), we get a palindrome (7668460648667).
The spelling of 2124040244455 in words is "two trillion, one hundred twenty-four billion, forty million, two hundred forty-four thousand, four hundred fifty-five".
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