Search a number
-
+
212411234153 = 1087195410519
BaseRepresentation
bin1100010111010010110…
…0100011011101101001
3202022021022012201001102
43011310230203131221
511440004233443103
6241325205531145
721226514462066
oct3056454433551
9668238181042
10212411234153
11820a0671108
1235200113ab5
1317051729801
14a3d0589c6d
1557d2d76e88
hex3174b23769

212411234153 has 4 divisors (see below), whose sum is σ = 212606645760. Its totient is φ = 212215822548.

The previous prime is 212411234117. The next prime is 212411234159. The reversal of 212411234153 is 351432114212.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212411234153 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (212411234159) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 97704173 + ... + 97706346.

It is an arithmetic number, because the mean of its divisors is an integer number (53151661440).

Almost surely, 2212411234153 is an apocalyptic number.

It is an amenable number.

212411234153 is a deficient number, since it is larger than the sum of its proper divisors (195411607).

212411234153 is a wasteful number, since it uses less digits than its factorization.

212411234153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 195411606.

The product of its digits is 5760, while the sum is 29.

Adding to 212411234153 its reverse (351432114212), we get a palindrome (563843348365).

The spelling of 212411234153 in words is "two hundred twelve billion, four hundred eleven million, two hundred thirty-four thousand, one hundred fifty-three".

Divisors: 1 1087 195410519 212411234153