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21241343323 = 61348218743
BaseRepresentation
bin10011110010000101…
…010010110101011011
32000211100100001011101
4103302011102311123
5322000240441243
613431431412231
71351244303434
oct236205226533
960740301141
1021241343323
1190102036a2
124149824077
132006916205
1410570d848b
15844c2154d
hex4f2152d5b

21241343323 has 4 divisors (see below), whose sum is σ = 21589562128. Its totient is φ = 20893124520.

The previous prime is 21241343309. The next prime is 21241343353. The reversal of 21241343323 is 32334314212.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21241343323 - 213 = 21241335131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21241343291 and 21241343300.

It is not an unprimeable number, because it can be changed into a prime (21241343353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 174109311 + ... + 174109432.

It is an arithmetic number, because the mean of its divisors is an integer number (5397390532).

Almost surely, 221241343323 is an apocalyptic number.

21241343323 is a deficient number, since it is larger than the sum of its proper divisors (348218805).

21241343323 is an equidigital number, since it uses as much as digits as its factorization.

21241343323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 348218804.

The product of its digits is 10368, while the sum is 28.

Adding to 21241343323 its reverse (32334314212), we get a palindrome (53575657535).

The spelling of 21241343323 in words is "twenty-one billion, two hundred forty-one million, three hundred forty-three thousand, three hundred twenty-three".

Divisors: 1 61 348218743 21241343323