212415040435031 has 4 divisors (see below), whose sum is σ = 242760046211472. Its totient is φ = 182070034658592.

The previous prime is 212415040434953. The next prime is 212415040435051. The reversal of 212415040435031 is 130534040514212.

212415040435031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-212415040435031 is a prime.

It is a super-2 number, since 2×212415040435031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 212415040434982 and 212415040435000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (212415040435051) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15172502888210 + ... + 15172502888223.

It is an arithmetic number, because the mean of its divisors is an integer number (60690011552868).

Almost surely, 2^{212415040435031} is an apocalyptic number.

212415040435031 is a deficient number, since it is larger than the sum of its proper divisors (30345005776441).

212415040435031 is an equidigital number, since it uses as much as digits as its factorization.

212415040435031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30345005776440.

The product of its (nonzero) digits is 57600, while the sum is 35.

Adding to 212415040435031 its reverse (130534040514212), we get a palindrome (342949080949243).

The spelling of 212415040435031 in words is "two hundred twelve trillion, four hundred fifteen billion, forty million, four hundred thirty-five thousand, thirty-one".