Base | Representation |
---|---|
bin | 1001101010001111000100… |
… | …11100101010100110010111 |
3 | 2210012202101020200000020111 |
4 | 10311013202130222212113 |
5 | 10241013430041202210 |
6 | 113102343552343451 |
7 | 4321466532401215 |
oct | 465074234524627 |
9 | 83182336600214 |
10 | 21242412444055 |
11 | 684a947044090 |
12 | 2470b08b44b87 |
13 | bb11c66a5a8a |
14 | 5361d14d1cb5 |
15 | 26c86d23b88a |
hex | 1351e272a997 |
21242412444055 has 16 divisors (see below), whose sum is σ = 27808617420288. Its totient is φ = 15448822564000.
The previous prime is 21242412444013. The next prime is 21242412444083. The reversal of 21242412444055 is 55044421424212.
It is not a de Polignac number, because 21242412444055 - 239 = 20692656630167 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21242412443999 and 21242412444017.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1694670 + ... + 6734740.
It is an arithmetic number, because the mean of its divisors is an integer number (1738038588768).
Almost surely, 221242412444055 is an apocalyptic number.
21242412444055 is a deficient number, since it is larger than the sum of its proper divisors (6566204976233).
21242412444055 is a wasteful number, since it uses less digits than its factorization.
21242412444055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5116718.
The product of its (nonzero) digits is 409600, while the sum is 40.
Adding to 21242412444055 its reverse (55044421424212), we get a palindrome (76286833868267).
The spelling of 21242412444055 in words is "twenty-one trillion, two hundred forty-two billion, four hundred twelve million, four hundred forty-four thousand, fifty-five".
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