Base | Representation |
---|---|
bin | 1100010111010101111… |
… | …0111011101001110001 |
3 | 202022022020001122122220 |
4 | 3011311132323221301 |
5 | 11440021124043213 |
6 | 241330400551253 |
7 | 21230034644262 |
oct | 3056536735161 |
9 | 668266048586 |
10 | 212424440433 |
11 | 820a8071197 |
12 | 35204622529 |
13 | 170543a188a |
14 | a3d2226969 |
15 | 57d40d4e23 |
hex | 31757bba71 |
212424440433 has 48 divisors (see below), whose sum is σ = 307918420992. Its totient is φ = 130162464000.
The previous prime is 212424440419. The next prime is 212424440477. The reversal of 212424440433 is 334044424212.
It is not a de Polignac number, because 212424440433 - 26 = 212424440369 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212424440394 and 212424440403.
It is not an unprimeable number, because it can be changed into a prime (212424440633) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 8023728 + ... + 8050158.
It is an arithmetic number, because the mean of its divisors is an integer number (6414967104).
Almost surely, 2212424440433 is an apocalyptic number.
It is an amenable number.
212424440433 is a deficient number, since it is larger than the sum of its proper divisors (95493980559).
212424440433 is a wasteful number, since it uses less digits than its factorization.
212424440433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26694 (or 26675 counting only the distinct ones).
The product of its (nonzero) digits is 73728, while the sum is 33.
Adding to 212424440433 its reverse (334044424212), we get a palindrome (546468864645).
The spelling of 212424440433 in words is "two hundred twelve billion, four hundred twenty-four million, four hundred forty thousand, four hundred thirty-three".
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