Base | Representation |
---|---|
bin | 110000010011011101010110… |
… | …110000111110111011110001 |
3 | 1000212012101121102101200112010 |
4 | 300103131112300332323301 |
5 | 210321133112244341223 |
6 | 2031455054454153133 |
7 | 62514350032112130 |
oct | 6023352660767361 |
9 | 1025171542350463 |
10 | 212443423043313 |
11 | 61766827a12700 |
12 | 1b9b0b606527a9 |
13 | 91704375a2867 |
14 | 3a6646081b917 |
15 | 198621ab4a393 |
hex | c13756c3eef1 |
212443423043313 has 48 divisors (see below), whose sum is σ = 355935004064640. Its totient is φ = 110327064207360.
The previous prime is 212443423043309. The next prime is 212443423043387. The reversal of 212443423043313 is 313340324344212.
It is not a de Polignac number, because 212443423043313 - 22 = 212443423043309 is a prime.
It is not an unprimeable number, because it can be changed into a prime (212443423048313) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4098270 + ... + 21016247.
It is an arithmetic number, because the mean of its divisors is an integer number (7415312584680).
Almost surely, 2212443423043313 is an apocalyptic number.
It is an amenable number.
212443423043313 is a deficient number, since it is larger than the sum of its proper divisors (143491581021327).
212443423043313 is a wasteful number, since it uses less digits than its factorization.
212443423043313 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 25117878 (or 25117867 counting only the distinct ones).
The product of its (nonzero) digits is 497664, while the sum is 39.
Adding to 212443423043313 its reverse (313340324344212), we get a palindrome (525783747387525).
The spelling of 212443423043313 in words is "two hundred twelve trillion, four hundred forty-three billion, four hundred twenty-three million, forty-three thousand, three hundred thirteen".
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