Base | Representation |
---|---|
bin | 1100011001011111001… |
… | …0100001001001101111 |
3 | 202100210100002010010000 |
4 | 3012113302201021233 |
5 | 11442211000000421 |
6 | 241503441115343 |
7 | 21250224061653 |
oct | 3062762411157 |
9 | 670710063100 |
10 | 213000000111 |
11 | 82372a46748 |
12 | 35345328b53 |
13 | 171166c0c32 |
14 | a44884aa63 |
15 | 58198c6226 |
hex | 3197ca126f |
213000000111 has 20 divisors (see below), whose sum is σ = 318275069112. Its totient is φ = 141959886768.
The previous prime is 213000000097. The next prime is 213000000151. The reversal of 213000000111 is 111000000312.
It is not a de Polignac number, because 213000000111 - 25 = 213000000079 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 213000000093 and 213000000102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213000000151) by changing a digit.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 81525 + ... + 657758.
Almost surely, 2213000000111 is an apocalyptic number.
213000000111 is a deficient number, since it is larger than the sum of its proper divisors (105275069001).
213000000111 is an equidigital number, since it uses as much as digits as its factorization.
213000000111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 742852 (or 742843 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
Adding to 213000000111 its reverse (111000000312), we get a palindrome (324000000423).
The spelling of 213000000111 in words is "two hundred thirteen billion, one hundred eleven", and thus it is an aban number.
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