Base | Representation |
---|---|
bin | 110000011011100100110000… |
… | …010001110111110110011111 |
3 | 1000221011201010111110002022101 |
4 | 300123210300101313312133 |
5 | 210404302300003231421 |
6 | 2033003210510025531 |
7 | 62602552252311331 |
oct | 6033446021676637 |
9 | 1027151114402271 |
10 | 213001123102111 |
11 | 619612a6077303 |
12 | 1ba810651a82a7 |
13 | 91b0bc5826356 |
14 | 3a85448c7d451 |
15 | 19959ac122191 |
hex | c1b930477d9f |
213001123102111 has 4 divisors (see below), whose sum is σ = 213004352268072. Its totient is φ = 212997893936152.
The previous prime is 213001123102051. The next prime is 213001123102127. The reversal of 213001123102111 is 111201321100312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213001123102111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213001123132111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1614484036 + ... + 1614615961.
It is an arithmetic number, because the mean of its divisors is an integer number (53251088067018).
Almost surely, 2213001123102111 is an apocalyptic number.
213001123102111 is a deficient number, since it is larger than the sum of its proper divisors (3229165961).
213001123102111 is an equidigital number, since it uses as much as digits as its factorization.
213001123102111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3229165960.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 213001123102111 its reverse (111201321100312), we get a palindrome (324202444202423).
The spelling of 213001123102111 in words is "two hundred thirteen trillion, one billion, one hundred twenty-three million, one hundred two thousand, one hundred eleven".
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