Search a number
-
+
21300241101 = 37100080367
BaseRepresentation
bin10011110101100101…
…111110001011001101
32000222110011100201120
4103311211332023031
5322110330203401
613441334031153
71352561030166
oct236545761315
960873140646
1021300241101
119040481447
1241654a84b9
132015b98579
141060c6a76d
15849ea7836
hex4f597e2cd

21300241101 has 4 divisors (see below), whose sum is σ = 28400321472. Its totient is φ = 14200160732.

The previous prime is 21300241021. The next prime is 21300241111. The reversal of 21300241101 is 10114200312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21300241101 - 215 = 21300208333 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21300241111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3550040181 + ... + 3550040186.

It is an arithmetic number, because the mean of its divisors is an integer number (7100080368).

Almost surely, 221300241101 is an apocalyptic number.

It is an amenable number.

21300241101 is a deficient number, since it is larger than the sum of its proper divisors (7100080371).

21300241101 is an equidigital number, since it uses as much as digits as its factorization.

21300241101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7100080370.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 21300241101 its reverse (10114200312), we get a palindrome (31414441413).

The spelling of 21300241101 in words is "twenty-one billion, three hundred million, two hundred forty-one thousand, one hundred one".

Divisors: 1 3 7100080367 21300241101