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21300401213132 = 225325100303283
BaseRepresentation
bin1001101011111011000101…
…10110010000111011001100
32210102022001120202200211112
410311331202312100323030
510242441210202310012
6113145134053111152
74325621540660006
oct465754266207314
983368046680745
1021300401213132
1168724a4203628
1224801b13284b8
13bb68085559a2
14538d32c05376
1526e11410e122
hex135f62d90ecc

21300401213132 has 6 divisors (see below), whose sum is σ = 37275702122988. Its totient is φ = 10650200606564.

The previous prime is 21300401213129. The next prime is 21300401213137. The reversal of 21300401213132 is 23131210400312.

It is a junction number, because it is equal to n+sod(n) for n = 21300401213098 and 21300401213107.

It is not an unprimeable number, because it can be changed into a prime (21300401213137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2662550151638 + ... + 2662550151645.

It is an arithmetic number, because the mean of its divisors is an integer number (6212617020498).

Almost surely, 221300401213132 is an apocalyptic number.

It is an amenable number.

21300401213132 is a deficient number, since it is larger than the sum of its proper divisors (15975300909856).

21300401213132 is a wasteful number, since it uses less digits than its factorization.

21300401213132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5325100303287 (or 5325100303285 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 21300401213132 its reverse (23131210400312), we get a palindrome (44431611613444).

The spelling of 21300401213132 in words is "twenty-one trillion, three hundred billion, four hundred one million, two hundred thirteen thousand, one hundred thirty-two".

Divisors: 1 2 4 5325100303283 10650200606566 21300401213132