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213024434341 = 327165125171
BaseRepresentation
bin1100011001100100111…
…1101110100010100101
3202100212001001111120111
43012121033232202211
511442233223344331
6241510112533021
721250641546535
oct3063117564245
9670761044514
10213024434341
1182385815524
1235351551171
131711b797764
14a44bbab4c5
15581bb00db1
hex31993ee8a5

213024434341 has 4 divisors (see below), whose sum is σ = 213089562784. Its totient is φ = 212959305900.

The previous prime is 213024434339. The next prime is 213024434383. The reversal of 213024434341 is 143434420312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213024434341 - 21 = 213024434339 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213024434041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32559315 + ... + 32565856.

It is an arithmetic number, because the mean of its divisors is an integer number (53272390696).

Almost surely, 2213024434341 is an apocalyptic number.

It is an amenable number.

213024434341 is a deficient number, since it is larger than the sum of its proper divisors (65128443).

213024434341 is an equidigital number, since it uses as much as digits as its factorization.

213024434341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65128442.

The product of its (nonzero) digits is 27648, while the sum is 31.

Adding to 213024434341 its reverse (143434420312), we get a palindrome (356458854653).

The spelling of 213024434341 in words is "two hundred thirteen billion, twenty-four million, four hundred thirty-four thousand, three hundred forty-one".

Divisors: 1 3271 65125171 213024434341