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2130301304042 = 21065150652021
BaseRepresentation
bin11110111111111111110…
…110100011110011101010
321112122200100201221000212
4132333333312203303222
5234400324113212132
64310351422101122
7306623565212612
oct36777766436352
97478610657025
102130301304042
1175150160511a
122a4a4971a7a2
13125b6a9a2402
147516dd8ba42
153a63250b5b2
hex1efffda3cea

2130301304042 has 4 divisors (see below), whose sum is σ = 3195451956066. Its totient is φ = 1065150652020.

The previous prime is 2130301304023. The next prime is 2130301304057. The reversal of 2130301304042 is 2404031030312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 2128473827041 + 1827477001 = 1458929^2 + 42749^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2130301303999 and 2130301304017.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 532575326009 + ... + 532575326012.

Almost surely, 22130301304042 is an apocalyptic number.

2130301304042 is a deficient number, since it is larger than the sum of its proper divisors (1065150652024).

2130301304042 is a wasteful number, since it uses less digits than its factorization.

2130301304042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1065150652023.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 2130301304042 its reverse (2404031030312), we get a palindrome (4534332334354).

The spelling of 2130301304042 in words is "two trillion, one hundred thirty billion, three hundred one million, three hundred four thousand, forty-two".

Divisors: 1 2 1065150652021 2130301304042