Base | Representation |
---|---|
bin | 11111000000000000011… |
… | …000100100100011110111 |
3 | 21112122200222111220110101 |
4 | 133000000120210203313 |
5 | 234400333404020043 |
6 | 4310352341134531 |
7 | 306624034045666 |
oct | 37000030444367 |
9 | 7478628456411 |
10 | 2130310220023 |
11 | 7515066448a7 |
12 | 2a4a506ba447 |
13 | 125b6c7a473b |
14 | 7517122cddd |
15 | 3a6331bd24d |
hex | 1f0006248f7 |
2130310220023 has 4 divisors (see below), whose sum is σ = 2144607604200. Its totient is φ = 2116012835848.
The previous prime is 2130310219997. The next prime is 2130310220083. The reversal of 2130310220023 is 3200220130312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2130310220023 - 213 = 2130310211831 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2130310220083) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7148691865 + ... + 7148692162.
It is an arithmetic number, because the mean of its divisors is an integer number (536151901050).
Almost surely, 22130310220023 is an apocalyptic number.
2130310220023 is a deficient number, since it is larger than the sum of its proper divisors (14297384177).
2130310220023 is a wasteful number, since it uses less digits than its factorization.
2130310220023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14297384176.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 2130310220023 its reverse (3200220130312), we get a palindrome (5330530350335).
The spelling of 2130310220023 in words is "two trillion, one hundred thirty billion, three hundred ten million, two hundred twenty thousand, twenty-three".
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