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2130331000000 = 265672711123
BaseRepresentation
bin11111000000000001100…
…111110101110011000000
321112122202102121122020011
4133000001213311303000
5234400404214000000
64310354402354304
7306624405504010
oct37000147656300
97478672548204
102130331000000
11751517348135
122a4a5765b994
13125b73b9bb98
1475173cbbc40
153a634e252ba
hex1f0019f5cc0

2130331000000 has 392 divisors, whose sum is σ = 6066712345088. Its totient is φ = 727056000000.

The previous prime is 2130330999967. The next prime is 2130331000043. The reversal of 2130331000000 is 1330312.

It is a super-2 number, since 2×21303310000002 (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 1896999439 + ... + 1897000561.

Almost surely, 22130331000000 is an apocalyptic number.

2130331000000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 2130331000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (3033356172544).

2130331000000 is an abundant number, since it is smaller than the sum of its proper divisors (3936381345088).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2130331000000 is an frugal number, since it uses more digits than its factorization.

2130331000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1443 (or 1408 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 2130331000000 its reverse (1330312), we get a palindrome (2130332330312).

The spelling of 2130331000000 in words is "two trillion, one hundred thirty billion, three hundred thirty-one million", and thus it is an aban number.