Base | Representation |
---|---|
bin | 11111000000101001100… |
… | …001111101110011001011 |
3 | 21112201111002111020011210 |
4 | 133000221201331303023 |
5 | 234403242120023210 |
6 | 4310545041224203 |
7 | 306650115536424 |
oct | 37005141756313 |
9 | 7481432436153 |
10 | 2131000548555 |
11 | 75183028894a |
12 | 2a5003932063 |
13 | 125c4c808968 |
14 | 751d8baa64b |
15 | 3a673acee20 |
hex | 1f02987dccb |
2131000548555 has 32 divisors (see below), whose sum is σ = 3426291880704. Its totient is φ = 1130982051456.
The previous prime is 2131000548553. The next prime is 2131000548581. The reversal of 2131000548555 is 5558450001312.
It is not a de Polignac number, because 2131000548555 - 21 = 2131000548553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2131000548553) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2445412 + ... + 3200318.
It is an arithmetic number, because the mean of its divisors is an integer number (107071621272).
Almost surely, 22131000548555 is an apocalyptic number.
2131000548555 is a deficient number, since it is larger than the sum of its proper divisors (1295291332149).
2131000548555 is a wasteful number, since it uses less digits than its factorization.
2131000548555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 755835.
The product of its (nonzero) digits is 120000, while the sum is 39.
Adding to 2131000548555 its reverse (5558450001312), we get a palindrome (7689450549867).
The spelling of 2131000548555 in words is "two trillion, one hundred thirty-one billion, five hundred forty-eight thousand, five hundred fifty-five".
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