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21310010303 = 158091347967
BaseRepresentation
bin10011110110001011…
…001111001110111111
32001000010112200112212
4103312023033032333
5322120330312203
613442323251035
71353040045631
oct236613171677
961003480485
1021310010303
119045a4416a
124168819a7b
132017c0906a
141062290a51
1584ac871d8
hex4f62cf3bf

21310010303 has 4 divisors (see below), whose sum is σ = 21311374080. Its totient is φ = 21308646528.

The previous prime is 21310010299. The next prime is 21310010317. The reversal of 21310010303 is 30301001312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21310010303 - 22 = 21310010299 is a prime.

It is a super-2 number, since 2×213100103032 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21310010333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 658175 + ... + 689792.

It is an arithmetic number, because the mean of its divisors is an integer number (5327843520).

Almost surely, 221310010303 is an apocalyptic number.

21310010303 is a deficient number, since it is larger than the sum of its proper divisors (1363777).

21310010303 is a wasteful number, since it uses less digits than its factorization.

21310010303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1363776.

The product of its (nonzero) digits is 54, while the sum is 14.

Adding to 21310010303 its reverse (30301001312), we get a palindrome (51611011615).

The spelling of 21310010303 in words is "twenty-one billion, three hundred ten million, ten thousand, three hundred three".

Divisors: 1 15809 1347967 21310010303