Search a number
-
+
213101011311 = 371033670437
BaseRepresentation
bin1100011001110111001…
…1110110000101101111
3202101001101011000102120
43012131303312011233
511442412324330221
6241521450124023
721252561465156
oct3063563660557
9671041130376
10213101011311
1182414a68981
1235373120613
13171315c9a86
14a45802259d
1558236ca5c6
hex319dcf616f

213101011311 has 4 divisors (see below), whose sum is σ = 284134681752. Its totient is φ = 142067340872.

The previous prime is 213101011283. The next prime is 213101011369. The reversal of 213101011311 is 113110101312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213101011311 - 234 = 195921142127 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213101011381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35516835216 + ... + 35516835221.

It is an arithmetic number, because the mean of its divisors is an integer number (71033670438).

Almost surely, 2213101011311 is an apocalyptic number.

213101011311 is a deficient number, since it is larger than the sum of its proper divisors (71033670441).

213101011311 is an equidigital number, since it uses as much as digits as its factorization.

213101011311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71033670440.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 213101011311 its reverse (113110101312), we get a palindrome (326211112623).

Subtracting from 213101011311 its reverse (113110101312), we obtain a palindrome (99990909999).

The spelling of 213101011311 in words is "two hundred thirteen billion, one hundred one million, eleven thousand, three hundred eleven".

Divisors: 1 3 71033670437 213101011311