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2131021100122 = 21065510550061
BaseRepresentation
bin11111000000101010110…
…000010111010001011010
321112201112112011100121221
4133000222300113101122
5234403312400200442
64310551053522254
7306650455323505
oct37005260272132
97481475140557
102131021100122
11751840945612
122a500a7a338a
13125c53b53155
14751db7da13c
153a6757de467
hex1f02ac1745a

2131021100122 has 4 divisors (see below), whose sum is σ = 3196531650186. Its totient is φ = 1065510550060.

The previous prime is 2131021100099. The next prime is 2131021100183. The reversal of 2131021100122 is 2210011201312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 1582264610161 + 548756489961 = 1257881^2 + 740781^2 .

It is a junction number, because it is equal to n+sod(n) for n = 2131021100096 and 2131021100105.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 532755275029 + ... + 532755275032.

Almost surely, 22131021100122 is an apocalyptic number.

2131021100122 is a deficient number, since it is larger than the sum of its proper divisors (1065510550064).

2131021100122 is a wasteful number, since it uses less digits than its factorization.

2131021100122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1065510550063.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 2131021100122 its reverse (2210011201312), we get a palindrome (4341032301434).

The spelling of 2131021100122 in words is "two trillion, one hundred thirty-one billion, twenty-one million, one hundred thousand, one hundred twenty-two".

Divisors: 1 2 1065510550061 2131021100122