Base | Representation |
---|---|
bin | 11111000000101010110… |
… | …111101001110100111011 |
3 | 21112201112122202110001001 |
4 | 133000222313221310323 |
5 | 234403313342324011 |
6 | 4310551202505431 |
7 | 306650510503120 |
oct | 37005267516473 |
9 | 7481478673031 |
10 | 2131023011131 |
11 | 751841a30363 |
12 | 2a500b365277 |
13 | 125c54371c21 |
14 | 751dbb76747 |
15 | 3a675a6a7c1 |
hex | 1f02ade9d3b |
2131023011131 has 64 divisors (see below), whose sum is σ = 2695608115200. Its totient is φ = 1642576548096.
The previous prime is 2131023011119. The next prime is 2131023011167. The reversal of 2131023011131 is 1311103201312.
It is a cyclic number.
It is not a de Polignac number, because 2131023011131 - 25 = 2131023011099 is a prime.
It is a super-2 number, since 2×21310230111312 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (19).
It is a junction number, because it is equal to n+sod(n) for n = 2131023011099 and 2131023011108.
It is not an unprimeable number, because it can be changed into a prime (2131023011191) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 218808460 + ... + 218818198.
It is an arithmetic number, because the mean of its divisors is an integer number (42118876800).
Almost surely, 22131023011131 is an apocalyptic number.
2131023011131 is a deficient number, since it is larger than the sum of its proper divisors (564585104069).
2131023011131 is a wasteful number, since it uses less digits than its factorization.
2131023011131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10328.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 2131023011131 its reverse (1311103201312), we get a palindrome (3442126212443).
The spelling of 2131023011131 in words is "two trillion, one hundred thirty-one billion, twenty-three million, eleven thousand, one hundred thirty-one".
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