Base | Representation |
---|---|
bin | 11111000000101011010… |
… | …110100011000101110011 |
3 | 21112201120012222220121021 |
4 | 133000223112203011303 |
5 | 234403322431010003 |
6 | 4310552052240311 |
7 | 306650636364025 |
oct | 37005326430563 |
9 | 7481505886537 |
10 | 2131031110003 |
11 | 751846562144 |
12 | 2a5012010097 |
13 | 125c55c49363 |
14 | 751dcc84015 |
15 | 3a67661a2bd |
hex | 1f02b5a3173 |
2131031110003 has 4 divisors (see below), whose sum is σ = 2171239244208. Its totient is φ = 2090822975800.
The previous prime is 2131031109947. The next prime is 2131031110037. The reversal of 2131031110003 is 3000111301312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2131031110003 - 233 = 2122441175411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (2131031110303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20104067023 + ... + 20104067128.
It is an arithmetic number, because the mean of its divisors is an integer number (542809811052).
Almost surely, 22131031110003 is an apocalyptic number.
2131031110003 is a deficient number, since it is larger than the sum of its proper divisors (40208134205).
2131031110003 is an equidigital number, since it uses as much as digits as its factorization.
2131031110003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40208134204.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 2131031110003 its reverse (3000111301312), we get a palindrome (5131142411315).
The spelling of 2131031110003 in words is "two trillion, one hundred thirty-one billion, thirty-one million, one hundred ten thousand, three".
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