Base | Representation |
---|---|
bin | 110000011101001010011100… |
… | …011101101100110010000111 |
3 | 1000221120010222002020021112002 |
4 | 300131022130131230302013 |
5 | 210413044404423333411 |
6 | 2033125305334015515 |
7 | 62613466130346020 |
oct | 6035123435546207 |
9 | 1027503862207462 |
10 | 213110312324231 |
11 | 619a3637594a53 |
12 | 1ba9a2584a759b |
13 | 91bb2a706871a |
14 | 3a8a8464cdc47 |
15 | 199874ce6433b |
hex | c1d29c76cc87 |
213110312324231 has 4 divisors (see below), whose sum is σ = 243554642656272. Its totient is φ = 182665981992192.
The previous prime is 213110312324207. The next prime is 213110312324237. The reversal of 213110312324231 is 132423213011312.
213110312324231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-213110312324231 is a prime.
It is a super-2 number, since 2×2131103123242312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 213110312324194 and 213110312324203.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213110312324237) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15222165166010 + ... + 15222165166023.
It is an arithmetic number, because the mean of its divisors is an integer number (60888660664068).
Almost surely, 2213110312324231 is an apocalyptic number.
213110312324231 is a deficient number, since it is larger than the sum of its proper divisors (30444330332041).
213110312324231 is an equidigital number, since it uses as much as digits as its factorization.
213110312324231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30444330332040.
The product of its (nonzero) digits is 5184, while the sum is 29.
Adding to 213110312324231 its reverse (132423213011312), we get a palindrome (345533525335543).
The spelling of 213110312324231 in words is "two hundred thirteen trillion, one hundred ten billion, three hundred twelve million, three hundred twenty-four thousand, two hundred thirty-one".
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