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21311040243155 = 513327862157587
BaseRepresentation
bin1001101100001110111001…
…11110111100010111010011
32210110022112000222102100112
410312013130332330113103
510243130002300240110
6113154053504311535
74326446305146155
oct466073476742723
983408460872315
1021311040243155
116876a63704323
1224822803125ab
13bb7812755c20
14539661b90ad5
1526e538149405
hex1361dcfbc5d3

21311040243155 has 8 divisors (see below), whose sum is σ = 27540421237392. Its totient is φ = 15737383564128.

The previous prime is 21311040243149. The next prime is 21311040243179. The reversal of 21311040243155 is 55134204011312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21311040243155 - 216 = 21311040177619 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 163931078729 + ... + 163931078858.

It is an arithmetic number, because the mean of its divisors is an integer number (3442552654674).

Almost surely, 221311040243155 is an apocalyptic number.

21311040243155 is a deficient number, since it is larger than the sum of its proper divisors (6229380994237).

21311040243155 is a wasteful number, since it uses less digits than its factorization.

21311040243155 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 327862157605.

The product of its (nonzero) digits is 14400, while the sum is 32.

Adding to 21311040243155 its reverse (55134204011312), we get a palindrome (76445244254467).

The spelling of 21311040243155 in words is "twenty-one trillion, three hundred eleven billion, forty million, two hundred forty-three thousand, one hundred fifty-five".

Divisors: 1 5 13 65 327862157587 1639310787935 4262208048631 21311040243155