Search a number
-
+
213111120223 = 1361315654971
BaseRepresentation
bin1100011001111001101…
…0011010000101011111
3202101002002011121020201
43012132122122011133
511442422421321343
6241522450524331
721253043430211
oct3063632320537
9671062147221
10213111120223
118241a742951
12353765966a7
1317133729091
14a4594d45b1
15582452594d
hex319e69a15f

213111120223 has 4 divisors (see below), whose sum is σ = 213126788808. Its totient is φ = 213095451640.

The previous prime is 213111120197. The next prime is 213111120227. The reversal of 213111120223 is 322021111312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213111120223 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 213111120223.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213111120227) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7813873 + ... + 7841098.

It is an arithmetic number, because the mean of its divisors is an integer number (53281697202).

Almost surely, 2213111120223 is an apocalyptic number.

213111120223 is a deficient number, since it is larger than the sum of its proper divisors (15668585).

213111120223 is a wasteful number, since it uses less digits than its factorization.

213111120223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15668584.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 213111120223 its reverse (322021111312), we get a palindrome (535132231535).

The spelling of 213111120223 in words is "two hundred thirteen billion, one hundred eleven million, one hundred twenty thousand, two hundred twenty-three".

Divisors: 1 13613 15654971 213111120223