Base | Representation |
---|---|
bin | 11111000000110000101… |
… | …110011000101111011111 |
3 | 21112201210111121020210002 |
4 | 133000300232120233133 |
5 | 234404014014321101 |
6 | 4311005032204515 |
7 | 306653112461513 |
oct | 37006056305737 |
9 | 7481714536702 |
10 | 2131121245151 |
11 | 751892425aa8 |
12 | 2a503823973b |
13 | 125c6b817972 |
14 | 7520ac28143 |
15 | 3a67e4c1d6b |
hex | 1f030b98bdf |
2131121245151 has 4 divisors (see below), whose sum is σ = 2131163899704. Its totient is φ = 2131078590600.
The previous prime is 2131121245133. The next prime is 2131121245157. The reversal of 2131121245151 is 1515421211312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2131121245151 - 218 = 2131120983007 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131121245157) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21252245 + ... + 21352286.
It is an arithmetic number, because the mean of its divisors is an integer number (532790974926).
Almost surely, 22131121245151 is an apocalyptic number.
2131121245151 is a deficient number, since it is larger than the sum of its proper divisors (42654553).
2131121245151 is an equidigital number, since it uses as much as digits as its factorization.
2131121245151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42654552.
The product of its digits is 2400, while the sum is 29.
Adding to 2131121245151 its reverse (1515421211312), we get a palindrome (3646542456463).
The spelling of 2131121245151 in words is "two trillion, one hundred thirty-one billion, one hundred twenty-one million, two hundred forty-five thousand, one hundred fifty-one".
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