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213113301 = 371037767
BaseRepresentation
bin11001011001111…
…01100111010101
3112212000021111020
430230331213111
5414024111201
633051431353
75165301402
oct1454754725
9485007436
10213113301
11aa32a1a5
125b455559
13351c8c5b
14204372a9
1513a99a36
hexcb3d9d5

213113301 has 4 divisors (see below), whose sum is σ = 284151072. Its totient is φ = 142075532.

The previous prime is 213113297. The next prime is 213113317. The reversal of 213113301 is 103311312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213113301 - 22 = 213113297 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213113701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35518881 + ... + 35518886.

It is an arithmetic number, because the mean of its divisors is an integer number (71037768).

Almost surely, 2213113301 is an apocalyptic number.

It is an amenable number.

213113301 is a deficient number, since it is larger than the sum of its proper divisors (71037771).

213113301 is an equidigital number, since it uses as much as digits as its factorization.

213113301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 71037770.

The product of its (nonzero) digits is 54, while the sum is 15.

The square root of 213113301 is about 14598.4006315760. The cubic root of 213113301 is about 597.3151343028.

Adding to 213113301 its reverse (103311312), we get a palindrome (316424613).

The spelling of 213113301 in words is "two hundred thirteen million, one hundred thirteen thousand, three hundred one".

Divisors: 1 3 71037767 213113301