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21312040431 = 3116131053539
BaseRepresentation
bin10011110110010010…
…111110110111101111
32001000021100211100210
4103312102332313233
5322121340243211
613442434553503
71353063232443
oct236622766757
961007324323
1021312040431
119047100460
124169438893
13201846a116
14106265c823
1584b0389a6
hex4f64bedef

21312040431 has 16 divisors (see below), whose sum is σ = 31049930880. Its totient is φ = 12895305120.

The previous prime is 21312040411. The next prime is 21312040447. The reversal of 21312040431 is 13404021312.

It is not a de Polignac number, because 21312040431 - 211 = 21312038383 is a prime.

It is a super-2 number, since 2×213120404312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21312040398 and 21312040407.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21312040411) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 506541 + ... + 546998.

It is an arithmetic number, because the mean of its divisors is an integer number (1940620680).

Almost surely, 221312040431 is an apocalyptic number.

21312040431 is a deficient number, since it is larger than the sum of its proper divisors (9737890449).

21312040431 is a wasteful number, since it uses less digits than its factorization.

21312040431 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1054166.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 21312040431 its reverse (13404021312), we get a palindrome (34716061743).

The spelling of 21312040431 in words is "twenty-one billion, three hundred twelve million, forty thousand, four hundred thirty-one".

Divisors: 1 3 11 33 613 1839 6743 20229 1053539 3160617 11588929 34766787 645819407 1937458221 7104013477 21312040431