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2131210202013 = 322310295701459
BaseRepresentation
bin11111000000110110000…
…001101110101110011101
321112202000200222201122200
4133000312001232232131
5234404204302431023
64311021531002113
7306655242551124
oct37006601565635
97482020881580
102131210202013
11751928664672
122a5061b99339
13125c84092b69
1475218982abb
153a6871e4743
hex1f03606eb9d

2131210202013 has 12 divisors (see below), whose sum is σ = 3212258855520. Its totient is φ = 1359032592456.

The previous prime is 2131210201997. The next prime is 2131210202113. The reversal of 2131210202013 is 3102020121312.

It is not a de Polignac number, because 2131210202013 - 24 = 2131210201997 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2131210202113) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5147850523 + ... + 5147850936.

It is an arithmetic number, because the mean of its divisors is an integer number (267688237960).

Almost surely, 22131210202013 is an apocalyptic number.

2131210202013 is a gapful number since it is divisible by the number (23) formed by its first and last digit.

It is an amenable number.

2131210202013 is a deficient number, since it is larger than the sum of its proper divisors (1081048653507).

2131210202013 is a wasteful number, since it uses less digits than its factorization.

2131210202013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10295701488 (or 10295701485 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 2131210202013 its reverse (3102020121312), we get a palindrome (5233230323325).

The spelling of 2131210202013 in words is "two trillion, one hundred thirty-one billion, two hundred ten million, two hundred two thousand, thirteen".

Divisors: 1 3 9 23 69 207 10295701459 30887104377 92661313131 236801133557 710403400671 2131210202013